C
Cold-B-Hearts
Guest
I have seen some members trying to explanation the jag gene on here but have been incorrect. Im going to attempt to explain the jag gene to a novice keeper who understands the genetics behind breeding a more common morph like albinos.
Jaguar is a co-dom mutation. Co-Dominance is when the gene can be visibly seen (in its heterozygous form) when only sitting on one allele. All living organisms have two alleles for each trait. Heterozygous is when one allele has a specific gene(along with others) on it and the other allele has another gene along with others.
I remember co dominance by reminding myself that it is two dominant traits working together, that are both visibly expressed. Think of COworkers and how they both work together.
SO.. this means that the jag gene only needs to be present on one allele for it to been show in the phenotype.. in other words if the jag gene is sitting on one allele its a jag.
If the Jag gene sits on BOTH alleles this means the recessive mutation will be shown. The recessive mutation for the jaguar gene is lethal (breeding jag X jag).... NO this does not mean if you breed a Jag to a Jag all the babies will die. Only 25% of the babies will be caring the jag gene on BOTH alleles... This is the recessive form of the jag gene these will be the dead leusistics
As you can see from the above co-dominance where the mutated and normal allele both contribute equally to the function of a cell/organism is difficult to explain in general and it is better to relate it to the function of the mutated protein in a real world situation
Quoted -David Wynick, University of Bristol
Lets look at it from another angle. Imagine breeding albino darwin carpet pythons. Hets for this example are our jags, normal's are our sibs/normals and albinos are out dead leucys.
Breeding a Het to a normal (jag to normal) would produce 50% normals and 50% hets(jags). However if you where to breed a HET to a HET you would produce 25%albino 50%hets and 25%normals imagining this was a jag to jag pairing it would produce 25%dead leusistics 50% jaguars and 25% sibs.
The only difference is that Hets do not have a visible phenotype and jaguars do. To explain this futher breeding a het to het produces 1/4 albino 3/4 66% het for albinos. this means when breeding jags you can visibly see what 66% are jags and what 33% and normals. (If you where to personaly breed Jag x Jag knowing you will get leusistics)
i don't know how well i quickly explained this to people that have minimum knowledge of genetics but i hope i can make someone understand this mutation. Feel free to Pm me, reply to this thread or Quote me for any questions.
Also could i suggest to mods making a genetics section to post all genetic related posts.
Cheers Liam
Jaguar is a co-dom mutation. Co-Dominance is when the gene can be visibly seen (in its heterozygous form) when only sitting on one allele. All living organisms have two alleles for each trait. Heterozygous is when one allele has a specific gene(along with others) on it and the other allele has another gene along with others.
I remember co dominance by reminding myself that it is two dominant traits working together, that are both visibly expressed. Think of COworkers and how they both work together.
SO.. this means that the jag gene only needs to be present on one allele for it to been show in the phenotype.. in other words if the jag gene is sitting on one allele its a jag.
If the Jag gene sits on BOTH alleles this means the recessive mutation will be shown. The recessive mutation for the jaguar gene is lethal (breeding jag X jag).... NO this does not mean if you breed a Jag to a Jag all the babies will die. Only 25% of the babies will be caring the jag gene on BOTH alleles... This is the recessive form of the jag gene these will be the dead leusistics
As you can see from the above co-dominance where the mutated and normal allele both contribute equally to the function of a cell/organism is difficult to explain in general and it is better to relate it to the function of the mutated protein in a real world situation
Quoted -David Wynick, University of Bristol
Lets look at it from another angle. Imagine breeding albino darwin carpet pythons. Hets for this example are our jags, normal's are our sibs/normals and albinos are out dead leucys.
Breeding a Het to a normal (jag to normal) would produce 50% normals and 50% hets(jags). However if you where to breed a HET to a HET you would produce 25%albino 50%hets and 25%normals imagining this was a jag to jag pairing it would produce 25%dead leusistics 50% jaguars and 25% sibs.
The only difference is that Hets do not have a visible phenotype and jaguars do. To explain this futher breeding a het to het produces 1/4 albino 3/4 66% het for albinos. this means when breeding jags you can visibly see what 66% are jags and what 33% and normals. (If you where to personaly breed Jag x Jag knowing you will get leusistics)
i don't know how well i quickly explained this to people that have minimum knowledge of genetics but i hope i can make someone understand this mutation. Feel free to Pm me, reply to this thread or Quote me for any questions.
Also could i suggest to mods making a genetics section to post all genetic related posts.
Cheers Liam
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