Thor1
Well-Known Member
albinoxalbino = 100% albino
Ablinoxhet =50% albino 50% het
Albino x normal= 100% hets
het x normal = 50% normal 50% hets
Ablinoxhet =50% albino 50% het
Albino x normal= 100% hets
het x normal = 50% normal 50% hets
Actually it does... :shock: And it answers my last questions. Thanks.peterjohnson64 said:does this help?
Thor1 said:I am wondering, should we try to explain the whole genotype/phenotype thing?
Sdaji said:SnakeWrangler: It depends on the trait. Few traits are 100% Mendelian. Most forms of albinism are about as close to true recessive as they get. If the trait is codominant, the heterozygotes have their own phenotype (which can even be outside the range of either homozygote), if the trait is dominant, the hets look the same as the homozygous mutant form (both "XX" and "xx" are homozygous).
peterjohnson64 said:Sdaji said:SnakeWrangler: It depends on the trait. Few traits are 100% Mendelian. Most forms of albinism are about as close to true recessive as they get. If the trait is codominant, the heterozygotes have their own phenotype (which can even be outside the range of either homozygote), if the trait is dominant, the hets look the same as the homozygous mutant form (both "XX" and "xx" are homozygous).
But Arj, from the point of view of us laymen punters, we can't look at a snake and say, "Oh, look, thats a het for albino". We are at the whim of the bloke selling it as a Prob., Poss. or Def. Het.
Thor1 said:as far as i know hets look the same as normals so there is no certain way to tell.
unless you are rolling in money and get the dna checked out.
and if anyone is rolling in money let me know how i can help you spend it!!
xX bred with XX = het x normal = 25 / 75peterjohnson64 said:if you get an xX and breed it with an XX you need to draw a matric but basically you will get 25% xX's and 75% XX's so you have all normal looking snakes of which 25% (on average) are het for albino.
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